JEE Advanced 2021 Paper 2 · Q08 · Electrolysis & Faraday's Laws
The value of $y$ is _____.
Reveal answer + step-by-step solution
Correct answer:0.88
Solution
From Q.7, $\alpha = y/4$ and $\alpha = 0.22$. So $y = 4\alpha = 4 \times 0.22 = 0.88$.
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