JEE Advanced 2023 Paper 1 · Q06 · Kinetic Theory of Gases
One mole of an ideal gas expands adiabatically from an initial state $(T_A, V_0)$ to final state $(T_f, 5V_0)$. Another mole of the same gas expands isothermally from a different initial state $(T_B, V_0)$ to the same final state $(T_f, 5V_0)$. The ratio of the specific heats at constant pressure and constant volume of this ideal gas is $\gamma$. What is the ratio $T_A/T_B$?
Reveal answer + step-by-step solution
Correct answer:A
Solution
Adiabatic: $T_A V_0^{\gamma-1} = T_f (5V_0)^{\gamma-1} \Rightarrow T_A = T_f \cdot 5^{\gamma-1}$. Isothermal: $T_B = T_f$. So $T_A/T_B = 5^{\gamma-1}$.
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