JEE Advanced 2023 Paper 1 · Q08 · Mole Concept & Stoichiometry
The stoichiometric reaction of $516$ g of dimethyldichlorosilane with water results in a tetrameric cyclic product $X$ in $75\%$ yield. The weight (in g) of $X$ obtained is ___. [Use molar mass (g·mol$^{-1}$): H = 1, C = 12, O = 16, Si = 28, Cl = 35.5]
Reveal answer + step-by-step solution
Correct answer:222
Solution
$(CH_3)_2SiCl_2$ has $M = 12\cdot 2 + 3\cdot 2 + 28 + 35.5\cdot 2 = 129$ g/mol. Moles = $516/129 = 4$ mol. The tetramer is cyclic $[(CH_3)_2SiO]_4$ with $M_{\text{tetramer}} = 4\times 74 = 296$ g/mol. From POAC on Si: $1 \times n_{\text{tetramer}} = 4 \times 4 / 4 = $ wait — $4$ mol of $(CH_3)_2SiCl_2$ → $1$ mol tetramer (since tetramer contains $4$ Si atoms). Theoretical mass = $1 \times 296 = 296$ g. At $75\%$ yield: $296 \times 0.75 = 222$ g.
Want to drill deeper? Open this question inside SolveKar AI and tap "Why?" on any step — the AI Mentor reads your full solution context and explains until it clicks. Download SolveKar AI →