JEE Advanced 2023 Paper 1 · Q14 · p-Block Elements (Groups 15-18)
Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their products given in List-II. List-I: (P) $P_2O_3 + 3H_2O \to$ (Q) $P_4 + 3NaOH + 3H_2O \to$ (R) $PCl_5 + CH_3COOH \to$ (S) $H_3PO_2 + 2H_2O + 4AgNO_3 \to$ List-II: (1) $P(O)(OCH_3)Cl_2$, (2) $H_3PO_3$, (3) $PH_3$, (4) $POCl_3$, (5) $H_3PO_4$
Reveal answer + step-by-step solution
Correct answer:D
Solution
(P) $P_2O_3 + 3H_2O \to 2H_3PO_3$ — (2). (Q) $P_4 + 3NaOH + 3H_2O \to PH_3 + 3NaH_2PO_2$ — (3). (R) $PCl_5 + CH_3COOH \to CH_3COCl + POCl_3 + HCl$ — (4). (S) $H_3PO_2 + 2H_2O + 4AgNO_3 \to H_3PO_4 + 4HNO_3 + 4Ag$ — (5).
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