JEE Advanced 2024 Paper 1 Q04 Chemistry Coordination Chemistry Isomerism in Coordination Compounds Medium

JEE Advanced 2024 Paper 1 · Q04 · Isomerism in Coordination Compounds

Among the following options, select the option in which each complex in $\mathbf{Set\text{-}I}$ shows geometrical isomerism and the two complexes in $\mathbf{Set\text{-}II}$ are ionization isomers of each other. [en = $H_2NCH_2CH_2NH_2$]

  1. A. $\mathbf{Set\text{-}I}$: $[Ni(CO)_4]$ and $[PdCl_2(PPh_3)_2]$; $\mathbf{Set\text{-}II}$: $[Co(NH_3)_5Cl]SO_4$ and $[Co(NH_3)_5(SO_4)]Cl$
  2. B. $\mathbf{Set\text{-}I}$: $[Co(en)(NH_3)_2Cl_2]$ and $[PdCl_2(PPh_3)_2]$; $\mathbf{Set\text{-}II}$: $[Co(NH_3)_6][Cr(CN)_6]$ and $[Cr(NH_3)_6][Co(CN)_6]$
  3. C. $\mathbf{Set\text{-}I}$: $[Co(NH_3)_3(NO_2)_3]$ and $[Co(en)_2Cl_2]$; $\mathbf{Set\text{-}II}$: $[Co(NH_3)_5Cl]SO_4$ and $[Co(NH_3)_5(SO_4)]Cl$
  4. D. $\mathbf{Set\text{-}I}$: $[Cr(NH_3)_6]Cl_3$ and $[Co(en)(NH_3)_2Cl_2]$; $\mathbf{Set\text{-}II}$: $[Cr(H_2O)_6]Cl_3$ and $[Cr(H_2O)_5Cl]Cl_2 \cdot H_2O$
Reveal answer + step-by-step solution

Correct answer:C

Solution

Set-I (geometrical isomers): $[Co(NH_3)_3(NO_2)_3]$ has $MA_3B_3$ geometry — exhibits $fac$/$mer$ isomers. $[Co(en)_2Cl_2]^+$ has $cis$/$trans$ isomers. Set-II (ionization isomers): $[Co(NH_3)_5Cl]SO_4$ and $[Co(NH_3)_5(SO_4)]Cl$ differ in the ion exchanged between the inner sphere and outside the coordination sphere, giving different ions in solution — definition of ionization isomerism. Hence option (C). $[Ni(CO)_4]$ is tetrahedral (no GI); $[Cr(NH_3)_6]Cl_3$ has no GI; option (D) Set-II is hydrate, not ionization.

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