JEE Advanced 2024 Paper 1 Q05 Chemistry Physical Chemistry Atomic Structure Medium

JEE Advanced 2024 Paper 1 · Q05 · Atomic Structure

Among the following, the correct statement(s) for electrons in an atom is(are)

  1. A. Uncertainty principle rules out the existence of definite paths for electrons.
  2. B. The energy of an electron in 2s orbital of an atom is lower than the energy of an electron that is infinitely far away from the nucleus.
  3. C. According to Bohr's model, the most negative energy value for an electron is given by $n = 1$, which corresponds to the most stable orbit.
  4. D. According to Bohr's model, the magnitude of velocity of electrons increases with increase in values of $n$.
JEE Advanced multi-correct — pick every correct option, then check.
Reveal answer + step-by-step solution

Correct answer:A, B, C

Solution

(A) Heisenberg's uncertainty principle implies $\Delta x \cdot \Delta p \ge h/4\pi$, so a precise trajectory (definite path) cannot be assigned — TRUE. (B) Energy of an electron at infinity is taken as $0$. The 2s electron has $E_n = -13.6 Z^2 / n^2 < 0$, hence lower than the free electron at infinity — TRUE. (C) For $n=1$, $E_1 = -13.6 \, \text{eV}$ (most negative, hence most stable / ground state) — TRUE. (D) Bohr velocity $v_n \propto Z/n$, so $v$ DECREASES with $n$ — FALSE. Hence (A), (B), (C) are correct.

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