JEE Advanced 2024 Paper 1 Q07 Chemistry Chemical Bonding Octet Rule & Lewis Structures Medium

JEE Advanced 2024 Paper 1 · Q07 · Octet Rule & Lewis Structures

The option(s) in which at least three molecules follow Octet Rule is(are)

  1. A. $CO_2, C_2H_4, NO$ and $HCl$
  2. B. $NO_2, O_3, HCl$ and $H_2SO_4$
  3. C. $BCl_3, NO, NO_2$ and $H_2SO_4$
  4. D. $CO_2, BCl_3, O_3$ and $C_2H_4$
JEE Advanced multi-correct — pick every correct option, then check.
Reveal answer + step-by-step solution

Correct answer:A, D

Solution

A molecule follows the octet rule if every main-group atom (except H, which gets duet) has 8 electrons. Counting how many molecules in each option satisfy this: (A) $CO_2$ ✓, $C_2H_4$ ✓, $NO$ ✗ (odd-electron, 11 valence $e^-$), $HCl$ ✓ — three follow octet ✓. (B) $NO_2$ ✗ (odd $e^-$), $O_3$ ✓, $HCl$ ✓, $H_2SO_4$ ✗ (S has expanded octet, 12 $e^-$) — only two follow. (C) $BCl_3$ ✗ (B has 6 $e^-$ — incomplete octet), $NO$ ✗, $NO_2$ ✗, $H_2SO_4$ ✗ — none. (D) $CO_2$ ✓, $BCl_3$ ✗, $O_3$ ✓, $C_2H_4$ ✓ — three follow ✓. Hence (A) and (D).

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