JEE Advanced 2024 Paper 2 Q08 Mathematics Algebra Sequences & Series Medium

JEE Advanced 2024 Paper 2 · Q08 · Sequences & Series

Let $f : \mathbb{R} \to \mathbb{R}$ be a function such that $f(x + y) = f(x) + f(y)$ for all $x, y \in \mathbb{R}$, and $g : \mathbb{R} \to (0, \infty)$ be a function such that $g(x + y) = g(x)\,g(y)$ for all $x, y \in \mathbb{R}$. If $f\!\left(\dfrac{-3}{5}\right) = 12$ and $g\!\left(\dfrac{-1}{3}\right) = 2$, then the value of $f\!\left(\dfrac{1}{4}\right) + g(-2) - 8\,g(0)$ is ______.

Reveal answer + step-by-step solution

Correct answer:51

Solution

The functional equations give $f(x) = kx$ and $g(x) = a^{x}$ for some constants. From $f(-3/5) = 12$: $-3k/5 = 12 \Rightarrow k = -20$. From $g(-1/3) = 2$: $a^{-1/3} = 2 \Rightarrow a = 1/8$. Hence $f(1/4) = -5$, $g(-2) = (1/8)^{-2} = 64$, and $g(0) = 1$. Required value $= -5 + 64 - 8(1) = 51$.

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