JEE Advanced 2025 Paper 1 Q01 Chemistry Inorganic Chemistry p-Block Elements (Groups 15-18) Easy

JEE Advanced 2025 Paper 1 · Q01 · p-Block Elements (Groups 15-18)

The heating of $NH_4NO_2$ at 60–70 °C and $NH_4NO_3$ at 200–250 °C is associated with the formation of nitrogen-containing compounds X and Y, respectively. X and Y, respectively, are:

  1. A. $N_2$ and $N_2O$
  2. B. $NH_3$ and $NO_2$
  3. C. $NO$ and $N_2O$
  4. D. $N_2$ and $NH_3$
Reveal answer + step-by-step solution

Correct answer:A

Solution

Ammonium nitrite on gentle heating decomposes via internal redox: $NH_4NO_2 \to N_2 + 2 H_2O$. So $X = N_2$. Ammonium nitrate on stronger heating (200–250 °C) gives nitrous oxide and water: $NH_4NO_3 \to N_2O + 2 H_2O$. So $Y = N_2O$. (Above ~300 °C the decomposition is more violent and gives $N_2 + O_2 + H_2O$, but at the stated temperature range the principal product is $N_2O$.) Answer: (A) $N_2$ and $N_2O$.

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