JEE Advanced 2025 Paper 2 Q01 Chemistry Coordination Chemistry Stability & Applications Medium

JEE Advanced 2025 Paper 2 · Q01 · Stability & Applications

During the sodium nitroprusside test of sulphide ion in an aqueous solution, one of the ligands coordinated to the metal ion is converted to:

  1. A. $NOS^-$
  2. B. $SCN^-$
  3. C. $SNO^-$
  4. D. $NCS^-$
Reveal answer + step-by-step solution

Correct answer:A

Solution

Sodium nitroprusside has the formula $Na_2[Fe(CN)_5(NO)]$. When it reacts with sulphide ion ($S^{2-}$) in aqueous solution, the coordinated $NO$ ligand reacts with $S^{2-}$ to form a coordinated nitrosyl-thiolate ($NOS^-$), giving the violet/purple-coloured complex $Na_4[Fe(CN)_5(NOS)]$. The $CN^-$ ligands remain unchanged. So the converted ligand is $NOS^-$.

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